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authorcrupest <crupest@outlook.com>2020-09-20 00:54:55 +0800
committercrupest <crupest@outlook.com>2020-09-20 00:54:55 +0800
commit56711685015cefea7406a04a6a7c7555e42ee8c8 (patch)
tree13caea6c81dfe99285c4283a9a03af5f2cdf6c61 /works
parentd4b70455c050038f57b485099e268369838d2695 (diff)
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import(solutions): Add problem 746 .
Diffstat (limited to 'works')
-rw-r--r--works/solutions/cpp/746.cpp35
1 files changed, 35 insertions, 0 deletions
diff --git a/works/solutions/cpp/746.cpp b/works/solutions/cpp/746.cpp
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+#include <vector>
+
+using std::vector;
+
+#include <algorithm>
+
+class Solution
+{
+public:
+ int minCostClimbingStairs(vector<int> &cost)
+ {
+ int count = cost.size();
+
+ // Total cost for index i means min cost of stepping through the number i stair,
+ // after which you are free to jump two or one stair.
+ // total_costs[i] is based on total_costs[i - 2] and total_costs[i - 1].
+ // Note:
+ // This is not min cost to step above the number i stair, which has no simple dependency
+ // relationship because based on whether it steps through the last step there are two situation.
+ // However with the restriction of stepping through that last stair, there is a
+ // dependency relationship. And we can easily get the final result by comparing total_costs[count - 2]
+ // and total_costs[count - 1]. But not just use total_costs[count - 1].
+ vector<int> total_costs(count);
+
+ total_costs[0] = cost[0];
+ total_costs[1] = cost[1];
+
+ for (int i = 2; i < count; i++)
+ {
+ total_costs[i] = std::min(total_costs[i - 2], total_costs[i - 1]) + cost[i];
+ }
+
+ return std::min(total_costs[count - 2], total_costs[count - 1]);
+ }
+};