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-rw-r--r--store/works/life/operating-system-challenge/.gitignore1
-rw-r--r--store/works/life/operating-system-challenge/1/README.md10
-rw-r--r--store/works/life/operating-system-challenge/1/effect.pngbin0 -> 136979 bytes
-rw-r--r--store/works/life/operating-system-challenge/1/main.cpp33
-rw-r--r--store/works/life/operating-system-challenge/1/sample.jpgbin0 -> 125777 bytes
-rw-r--r--store/works/life/operating-system-challenge/2/README.md10
-rw-r--r--store/works/life/operating-system-challenge/2/effect.pngbin0 -> 179599 bytes
-rw-r--r--store/works/life/operating-system-challenge/2/main.cpp73
-rw-r--r--store/works/life/operating-system-challenge/2/sample.jpgbin0 -> 82879 bytes
-rw-r--r--store/works/life/operating-system-challenge/3/README.md5
-rw-r--r--store/works/life/operating-system-challenge/3/main.cpp68
-rw-r--r--store/works/life/operating-system-challenge/3/problem.jpgbin0 -> 25702 bytes
-rw-r--r--store/works/life/operating-system-challenge/README.md1
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diff --git a/store/works/life/operating-system-challenge/.gitignore b/store/works/life/operating-system-challenge/.gitignore
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+*.exe
diff --git a/store/works/life/operating-system-challenge/1/README.md b/store/works/life/operating-system-challenge/1/README.md
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+> 挑战一:写一个程序,运行该进程时,你的电脑整体 CPU 利用率保持在 100%
+> 示例效果如
+> ![sample](sample.jpg)
+
+Transaltion: Write a program and make your CPU's usage rate 100%.
+
+Code is in `main.cpp`. Remember to not compile it with O2 optimization, or my dead loop will be eliminated.
+
+Final effect:
+![effect](effect.png)
diff --git a/store/works/life/operating-system-challenge/1/effect.png b/store/works/life/operating-system-challenge/1/effect.png
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diff --git a/store/works/life/operating-system-challenge/1/main.cpp b/store/works/life/operating-system-challenge/1/main.cpp
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+// Remember not to use O2 optimization!
+
+#include <thread>
+#include <vector>
+
+int main() {
+ std::vector<std::thread> threads;
+
+ // Because my CPU has 4-core and 8-threads. I open 8 threads.
+ for (int i = 0; i < 8; i++) {
+ std::thread t([] {
+ int i;
+ int j;
+ int k;
+ double d;
+ while (true) {
+ i = i + i;
+ j = j - j;
+ k = k * k;
+ d = d + d;
+ i = i & i;
+ j = j | j;
+ }
+ });
+ threads.push_back(std::move(t));
+ }
+
+ for (auto &t : threads) {
+ t.join();
+ }
+
+ return 0;
+}
diff --git a/store/works/life/operating-system-challenge/1/sample.jpg b/store/works/life/operating-system-challenge/1/sample.jpg
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diff --git a/store/works/life/operating-system-challenge/2/README.md b/store/works/life/operating-system-challenge/2/README.md
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+> 挑战二:写一个程序,运行该进程时,你计算机每一个核的 CPU 占用率是各不相同的有规律的曲线
+> 示例效果如:
+> ![sample](sample.jpg)
+
+Translation: Write a program and make each core of your CPU get a different but regular usage rate graph.
+
+Code is in `main.cpp`. Remember to not compile it with O2 optimization, or my loop will be eliminated.
+
+Final effect:
+![effect](effect.png)
diff --git a/store/works/life/operating-system-challenge/2/effect.png b/store/works/life/operating-system-challenge/2/effect.png
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diff --git a/store/works/life/operating-system-challenge/2/main.cpp b/store/works/life/operating-system-challenge/2/main.cpp
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+++ b/store/works/life/operating-system-challenge/2/main.cpp
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+#include <Windows.h>
+#include <cmath>
+
+DWORD WINAPI Thread1(_In_ LPVOID lpParameter) {
+ int i;
+ while (true) {
+ i++;
+ }
+ return 0;
+}
+
+DWORD WINAPI Thread2(_In_ LPVOID lpParameter) {
+ while (true) {
+ for (long long i = 0; i < 5000000000; i++)
+ ;
+ Sleep(10000);
+ }
+
+ return 0;
+}
+
+DWORD WINAPI Thread3(_In_ LPVOID lpParameter) {
+ while (true) {
+ for (int i = 0; i < 4000000; i++)
+ ;
+ Sleep(10);
+ }
+
+ return 0;
+}
+
+DWORD WINAPI Thread4(_In_ LPVOID lpParameter) {
+ LARGE_INTEGER frequency;
+ QueryPerformanceFrequency(&frequency);
+
+ LARGE_INTEGER count;
+ QueryPerformanceCounter(&count);
+
+ double current_y = 0;
+
+ while (true) {
+ for (int i = 0; i < 3000000.0 * (1.0 + current_y); i++)
+ ;
+ Sleep(10 * (1 - current_y));
+
+ LARGE_INTEGER new_count;
+ QueryPerformanceCounter(&new_count);
+
+ auto s = (new_count.QuadPart - count.QuadPart) / frequency.QuadPart;
+ current_y = std::sin(s / 30.0 * 2 * 3.1415926535) * 0.6;
+ }
+
+ return 0;
+}
+
+int main() {
+ HANDLE thread1 = CreateThread(NULL, 0, Thread1, NULL, 0, NULL);
+ HANDLE thread2 = CreateThread(NULL, 0, Thread2, NULL, 0, NULL);
+ HANDLE thread3 = CreateThread(NULL, 0, Thread3, NULL, 0, NULL);
+ HANDLE thread4 = CreateThread(NULL, 0, Thread4, NULL, 0, NULL);
+
+ SetThreadAffinityMask(thread1, 1);
+ SetThreadAffinityMask(thread2, 1 << 1);
+ SetThreadAffinityMask(thread3, 1 << 2);
+ SetThreadAffinityMask(thread4, 1 << 3);
+
+ WaitForSingleObject(thread1, INFINITE);
+ WaitForSingleObject(thread2, INFINITE);
+ WaitForSingleObject(thread3, INFINITE);
+ WaitForSingleObject(thread4, INFINITE);
+
+ return 0;
+}
diff --git a/store/works/life/operating-system-challenge/2/sample.jpg b/store/works/life/operating-system-challenge/2/sample.jpg
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diff --git a/store/works/life/operating-system-challenge/3/README.md b/store/works/life/operating-system-challenge/3/README.md
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+![problem](problem.jpg)
+
+Translation: Use a lock to achieve that 3 threads print A, B, C in turn for 10 times. Output is `ABCABC...`
+
+Code is in `main.cpp`.
diff --git a/store/works/life/operating-system-challenge/3/main.cpp b/store/works/life/operating-system-challenge/3/main.cpp
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+#include <iostream>
+#include <mutex>
+#include <thread>
+
+int main() {
+ int turn = 1;
+ int count = 0;
+ std::mutex mutex;
+
+ auto thread_proc1 = [&] {
+ while (true) {
+ {
+ std::lock_guard<std::mutex> guard(mutex);
+ if (count >= 10)
+ break;
+ if (turn == 1) {
+ std::cout << "A" << std::endl;
+ turn = 2;
+ }
+ }
+
+ std::this_thread::yield();
+ }
+ };
+
+ auto thread_proc2 = [&] {
+ while (true) {
+ {
+ std::lock_guard<std::mutex> guard(mutex);
+ if (count >= 10)
+ break;
+ if (turn == 2) {
+ std::cout << "B" << std::endl;
+ turn = 3;
+ }
+ }
+
+ std::this_thread::yield();
+ }
+ };
+
+ auto thread_proc3 = [&] {
+ while (true) {
+ {
+ std::lock_guard<std::mutex> guard(mutex);
+ if (count >= 10)
+ break;
+ if (turn == 3) {
+ std::cout << "C" << std::endl;
+ turn = 1;
+ count++;
+ }
+ }
+
+ std::this_thread::yield();
+ }
+ };
+
+ std::thread thread1(thread_proc1);
+ std::thread thread2(thread_proc2);
+ std::thread thread3(thread_proc3);
+
+ thread1.join();
+ thread2.join();
+ thread3.join();
+
+ return 0;
+}
diff --git a/store/works/life/operating-system-challenge/3/problem.jpg b/store/works/life/operating-system-challenge/3/problem.jpg
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diff --git a/store/works/life/operating-system-challenge/README.md b/store/works/life/operating-system-challenge/README.md
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+Some challenges raised by my Operating System teacher, aka. Li Hao.